How many milliliters of a 8.50 M LiCl solution contain 45.8 g of LiCl?

Express your answer with the appropriate units.

127 mL is the volume for the 45.8 g of LiCl

Explanation:

Molarity of solution: 8.50 M

We know, from this data that 8.50 moles of solute (LiCl), are in 1L of solution

Let's find out the volume for the 45.8 g of LiCl, by a rule of three.

We convert the mass to moles, before: 45.8 g. 1mol / 42.39g = 1.08 moles

Therefore:

8.50 moles of LiCl are found in 1L of solution

Our 1.08 moles will be found in (1.08 mol. 1L) / 8.50 mol = 0.127 L

We can convert the volume from L to mL: 0.127L. 1000 mL/1L = 127mL

The 8.50M LiCl solution contains 127 mL of LiCl

Explanation:

Step 1: Data given

Concentration of the LiCl solution = 8.50 M

Mass of LiCl = 45.8 grams

Molar mass of LiCl = 42.39 g/mol

Step 2: Calculate moles of LiCl

Moles LiCl = mass LiCl / molar mass LiCl

Moles LiCl = 45.8 grams / 42.39 g/mol

Moles LiCl = 1.08 moles

Step 3: Calculate volume of the LiCl solution

Molarity = moles / volume

Volume = moles / molarity

Volume LiCl solution = 1.08 moles / 8.50 M

Volume LiCl solution = 0.127 L

Step 4: Convert volume from L to mL

0.127 L = 0.127 * 10³ mL = 127 mL

The 8.50M LiCl solution contains 127 mL of LiCl