I have an acid that is pH 4.33. What is the normality of the acid?

see explanation below

Explanation:

To do this problem, we need to know the identity of the acid. This is very important, because that will define how the normality can be calculated. If the pH is 4.33 we can assume we have a weak acid and monoprotic so the normality will be the same as molarity.

With this said, we just need to calculate the concentration of the acid. We have the pH and so, we can get the concentration.

[H⁺] = 10^ (-pH)

Replacing we have:

[H⁺] = 10^ (-4.33)

[H⁺] = 4.68x10⁻⁵ M

With this, the Normality will be the same and is:

N = 4.68x10⁻⁵ N

This is assuming we have a monoprotic acid. If we have a diprotic acid, the previous result would have to be divided by 2.