A gas storage tank has a volume of 3.5 x 10^5 m^3 when the temperature is 27 C and the pressure is 101 kPa. What os the new volume of the tank if the temperature drops to - 10 C and the pressure drops to 95 kPa

3.26*10⁵m³

Explanation:

Given dа ta:

Initial volume = 3.5*10⁵ m³

Initial temperature = 27 °C

Initial pressure = 101 Kpa

Final temperature = - 10°C

Final pressure = 95 Kpa

Final volume = ?

Solution:

Initial temperature = 27 °C (27+273 = 300 K)

Final temperature = - 10°C (-10+273 = 263 K)

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₂ = P₁V₁ T₂ / T₁ P₂

V₂ = 101 Kpa * 3.5*10⁵ m³ * 263 K / 300 K * 95 Kpa

V₂ = 92970.5 * 10⁵ kpa. m³. K / 28500 K. Kpa

V₂ = 3.26*10⁵m³