Read the given equation.

Na2O2 + CO2 → Na2CO3 + O2

What volume of O2 gas is produced from 4.60 liters of CO2, assuming all values are measured at STP?

1.20 liters

2.30 liters

5.20 liters

9.20 liters

B) 2.30 liters

Explanation:

I took the quiz and B was correct!

2.30 liters.

Explanation:

The balanced equation of the reaction is:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2O₂,

It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂. The no. of moles of CO₂ in (4.60 L) reacted can be calculated from the relation: PV = nRT.

P is the pressure of the gas (P = 1.0 atm at STP),

V is the volume of the gas (V = 4.60 L),

R is the general gas constant (R = 0.082 L. atm/mol. K),

T is the temperature of the gas (T = 273.0 K at STP).

∴ n = PV/RT = (1.0 atm) (4.6 L) / (0.082 L. atm/mol. K) (273.0 K) = 0.205 mol.

Using cross multiplication:

1.0 mole of CO₂ produces → 0.5 mole of O₂, from the stichiometry.

0.205 mole of CO₂ produces →? mole of O₂.

The no. of moles of O₂ produced from 4.60 L of CO₂ = (0.5 mole) (0.205 mole) / (1.0 mole) = 0.103 mole. ∴ The volume of O₂ produced from 4.60 L of CO₂ = nRT/P = (0.103 mol) (0.082 L. atm/mol. K) (273.0 K) / (1.0 atm) = 2.30 liters.