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22 August, 15:47

How many grams of N205 gas are in sample that has a volume of 2.00 liters at 298 k and 100

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  1. 22 August, 18:04
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    883.44g

    Explanation:

    let us assume that the unit of the pressure is given in "atm" since it was not clearly stated in this problem.

    Given parameters:

    Volume of gas = 2liters

    Temperature of gas = 298K

    Pressure on the gas = 100atm

    Unknown:

    Mass of the gas = ?

    Solution:

    Applying the ideal gas law and the mathematical equation will give us a problem where we can easily solve for the number of moles.

    After finding the number of moles, the mass is easy to deduce from it.

    Ideal gas equation is given as:

    PV = nRT

    where P is the pressure on the gas

    V is the volume of the gas

    n is the number of moles

    R is the gas constant = 0.082atm dm³mol⁻¹K⁻¹

    T is the temperature on the gas

    Now let us solve for the number of moles;

    100 x 2 = n x 0.082 x 298

    n = 8.18moles

    Since;

    mass = number of moles x molar mass

    Molar mass of N₂O₅ = 2 (14) + 5 (16) = 108g/mol

    Mass of N₂O₅ = 8.18 x 108 = 883.44g
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