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11 June, 19:01

When 0.250 moles of a gas is placed in a container at 298K, it exerts a pressure of 0.92 atm. What is the volume of the container? PV = nRT R = 0.0821 L·atm/mol·K options: 0.12L 0.55L 6.6L 8.3L

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  1. 11 June, 22:40
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    PV = nRT

    We are to get the answer for the volume. Hence we make V the subject of the formula.

    V = nRT/P

    Where n = 0.250, R = 0.0821, P = 0.92 and T = 298

    V = (0.250*0.0821*298) : 0.92

    V = 6.11645:0.92

    V = 6.64

    V = 6.6L
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