A sample of a gas has an initial pressure of 0.987 atm and a volume of 12.8 L. What is the

final pressure if the volume is increased to 25.6 L?

0.494 atm

Explanation:

Data obtained from the question include:

P1 (initial pressure) = 0.987 atm

V1 (initial volume) = 12.8 L

P2 (final pressure) = ?

V2 (final volume) = 25.6 L

Using the Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:

P1V1 = P2V2

0.987 x 12.8 = P2 x 25.6

Divide both side by 25.6

P2 = (0.987 x 12.8) / 25.6

P2 = 0.494 atm

Therefore, the final pressure of the gas is 0.494 atm