How many moles of H₂ would be required to produce 9.0 grams of water?

In 9.0 grams of water there are 0.11 mol of H₂.

Explanation:

The data we know is simple:

1 mole (H₂O) 18 g (H₂O)

- Taking this into account, a rule of 3 is made for 9.0 grams of water.

1 mole (H₂O) 18 g (H₂O)

X mole (H₂O) 9.0 g (H₂O)

- We clear the X =

X = 1 mol (H₂O) * 9 g (H₂O) / 18 g (H₂O)

X = 0.5 mol (H₂O)

- Now rule of 3 is done again but with the new dа ta:

0.5 mol (H₂O) 9.0 g (H₂O)

X mol (H₂) 2 g (H) (Which is the same as H₂)

- Again we clear X:

X = 2 g (H) * 0.5 mol (H₂O) / 9.0 g (H₂O)

X = 0.11 gr (H₂)