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4 November, 04:26

If you have 1.1 moles of magnesium nitrate then how many grams is that

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  1. 4 November, 05:13
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    Answer: 162.8 grams

    Explanation:

    Magnesium nitrate has a chemical formula of Mg (NO3) 2.

    Given that:

    Number of moles of Mg (NO3) 2 = 1.1 moles

    Mass in grams of Mg (NO3) 2 = ?

    For Molar mass of Mg (NO3) 2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g

    Mg (NO3) 2 = 24g + (14g + 16gx3) x 2

    = 24g + (14g + 48g) x 2

    = 24g + (62g) x 2

    = 24g + 124g

    = 148g/mol

    Now, apply the formula:

    Number of moles = Mass in grams / molar mass

    1.1 moles = Mass / 148g/mol

    Mass = 1.1 moles x 148g/mol

    Mass = 162.8 grams

    Thus, there are 162.8 grams of magnesium nitrate.
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