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1 November, 23:41

Calculate the Kelvin temperature to which 10.0 L of a gas at 27 °C would have to be heated to change the volume to 12.0 L. Units of Kelvin are assumed here for the answer you enter so just put the number value.

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  1. 2 November, 00:42
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    Hello!

    For this problem, we will be applying Charles' Law:

    V1/T1 = V2/T2

    Now that we have the formula, let's convert the temperature to Kelvin.

    27 + 273 = 300K

    Let's plug everything in now!

    10/300 = 12.0/x

    Simplified:

    1/30 = 12.0/x

    Cross-multiply:

    1x = 30*12.0

    x = 360

    Check!

    10/300 = 12/360

    300*12 = 360*10

    3600 = 3600

    Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.
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