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23 July, 16:33

How many liters are in 3.36 grams of F2 gas at STP

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  1. 23 July, 20:21
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    Volume = 3.98L

    Explanation:

    Volume = ?

    Mass = 3.36g

    Pressure at STP = 1atm

    Temperature at STP = 273.15k

    Molarmass = 18.99g/mol

    R = 0.082J/mol. K

    From ideal gas equation

    PV = nRT

    P = pressure

    V = volume the gas occupies

    n = number of moles,

    R = ideal gas constant

    T = temperature of the gas

    PV = nRT

    Number of moles = mass / molarmass

    n = 3.36 / 18.99

    n = 0.1769 moles

    PV = nRT

    Solve for V

    V = nRT / P

    V = (0.1769 * 0.082 * 273.15) / 1

    V = 3.96L

    The volume the gas occupies is 3.96L
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