What mass of water will be produced from 9.6 g of calcium hydroxide reacting with hcl

4.67g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

Ca (OH) 2 + 2HCl - > CaCl2 + 2H2O

Step 2:

Determination of the mass of Ca (OH) 2 that reacted and the mass of H2O produced from the balanced equation. This is illustrated below:

Molar Mass of Ca (OH) 2 = 40 + 2 (16 + 1) = 40 + 2 (17) = 40 + 34 = 74g/mol

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g

From the balanced equation above,

74g of Ca (OH) 2 reacted to produce 36g of H2O.

Step 3:

Determination of the mass of water (H2O) produced by the reaction 9.6g of calcium hydroxide, Ca (OH) 2.

This is illustrated below:

From the balanced equation above,

74g of Ca (OH) 2 reacted to produce 36g of H2O.

Therefore, 9.6g of Ca (OH) 2 will react to produce = (9.6 x 36) / 74 = 4.67g of H2O.

Therefore, the mass of the water (H2O) produced by reaction of 9.6g of calcium hydroxide, Ca (OH) 2 is 4.67g.