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13 January, 22:19

Consider two solutions: one formed by adding 10.0 grams of glucose (C6H12O6) to 1.0 L of water

and another formed by adding 10.0 grams of sucrose (C12H22O11) to 1.0 L of water. Which of the

two solutes produces the lower reduction in the vapor pressure of the solvent? Explain fully.

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  1. 13 January, 23:53
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    Lowering of vapour pressure of solvent is proportional to number of moles of solute dissolved in it per litre.

    No of moles of glucose dissolved

    = mass dissolved / molecular weight of glucose

    = 10 / 180

    =.055 moles.

    No of moles of sucrose dissolved = 10 / 342

    =.029 moles.

    So reduction in vapour pressure will be lower of solution dissolving sucrose. It is so because, no of moles of solute dissolved in it is low.
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