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6 March, 10:53

What mass (g) of potassium chloride is contained in 430.0 mL of a potassium chloride solution that has a chloride ion concentration of 0.193 M?

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  1. 6 March, 11:33
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    6.178 g.

    Explanation:

    KCl is ionized in the solution as:

    KCl → K⁺ + Cl⁻.

    ∴ [KCl] = [K⁺] = [Cl⁻] = 0.193 M.

    Molarity is defined as the no. of moles of the solute per 1.0 L of the solution.

    ∵ M = [ (mass/molar mass) KCl][ (1000) / (V of the solution) ].

    ∴ mass of KCl = (M) (molar mass of KCl) (V of the solution) / 1000 = (0.193 M) (74.55 g/mol) (430.0 mL) / 1000 = 6.178 g.
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