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10 November, 13:18

Match the standard reduction potentials for each half reaction and the electric potential for the voltaic cell.

Given:

half-cell:

Be

2

+



Be

reduction half-reaction:

Be

2

+

+

2

e

_



Be

E

0

=

half-cell:

Hg

2

+



Hg

reduction half-reaction:

Hg

2

+

+

2

e

_



Hg

E

0

=

anode:

Be

2

+

cathode:

Hg

2

+

E

cell

0

=

E

cathode

0

-

E

anode

0

E

cell

0

=

+5
Answers (1)
  1. 10 November, 15:38
    0
    halfcell
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