Question 2

20 pts

An ethylene gas torch requires 3200 L of gas at 3.00 atm. What will be the pressure of the gas if ethylene is supplied

by a 250.0 L tank?

O

0.231 atm

2.34 atm

38.4 atm

45.4 atm

38.4 atm

Explanation:

Data obtained from the question include:

V1 (initial volume) = 3200 L

P1 (initial pressure) = 3.00 atm

V2 (final volume) = 250.0 L

P2 (final pressure) = ?

Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:

P1V1 = P2V2

3 x 3200 = P2 x 250

Divide both side by 250

P2 = 3 x 3200/250

P2 = 38.4 atm

Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm