How many moles of sulfuric acid (H2SO4) are needed to react completely with 6.8 moles of lithium hydroxide (LiOH) ?

2LiOH + H2SO4 → Li2SO4 + 2H2O

A) 3.4 mol H2SO4

B) 6.8 mol H2SO4

C) 10.2 mol H2SO4

D) 13.6 mol H2SO4

answer: A) 3.4 mol H2SO4

A) 3.4 mole of H₂SO₄.

Explanation:

From the stichiometry of the reaction: 2 LiOH + H₂SO₄ → Li₂SO₄ + 2 H₂O It is clear that 2.0 moles of LiOH reacts with 1.0 mole of H₂SO₄ to produce 1.0 mole of Li₂SO₄ and 2.0 moles of H₂O.

Using cross multiplication:

1.0 mole of H₂SO₄ reacts completely with → 2.0 moles of LiOH

? mole of H₂SO₄ are needed to react completely with → 6.8 moles of LiOH

The number of moles of H₂SO₄ = (1.0 x 6.8) / (2.0) = 3.4 mole of H₂SO₄.