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27 November, 11:29

How much heat (in Joules) will be needed to vaporize 18.015 grams of liquid water at 100°C?

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  1. 27 November, 13:21
    0
    40659.855 J

    Explanation:

    From the question given above, we obtained the following:

    Mass (m) = 18.015g

    Heat of vaporisation (ΔHv) = 2257 J/g

    Heat (Q) = ?

    The heat required to vaporise the water can be calculated as follow:

    Q = mΔHv

    Q = 18.015 x 2257

    Q = 40659.855 J

    Therefore, the heat required to vaporise the water is 40659.855 J
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