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7 August, 03:03

The specific heat of copper is 0.4 J/g^ * C If a sample of copper absorbs 480J of energy and its temperature changes from 20.0 ^ * c to 60.0 ^ * C what mass of copper was heated?

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  1. 7 August, 04:41
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    The mass of copper that was heated is 30 g

    Explanation:

    The formula for the heat supplied, ΔH is;

    ΔH = m·c·Δt

    Where:

    ΔH = Heat supplied = 480 J

    m = Mass of the copper sample = Required

    c = Specific heat capacity of copper = 0.4 J / (g·°C)

    Δt = Change in temperature = T₂ - T₁ = 60° - 20° = 40°C

    T₁ = Initial temperature = 20°C

    T₂ = Final temperature = 60°C

    Therefore, plugging the values, we have;

    480 = m*0.4*40

    m = 480 / (0.4 * 40) = 30 g

    The mass of copper that was heated = 30 g.
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