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14 October, 01:20

You have the equations:

2H2O (l) →2H2 (g) + O2 (g), △H=572 kJ

2N2 (g) + 3H2 (g) →2NH3 (g), △H=-138 kJ

2NO2 (g) + 7H2 (g) →2NH3 (g) + 4H2O (l), △H=-1.18*103 kJ 2NO2 (g) →2N2 (g) + 2O2 (g), △H=□

What is the missing △H?

-1.38*103 kJ

+99.0 kJ

+1.38 * 10³ kJ

-138 kJ

+5
Answers (1)
  1. 14 October, 02:38
    0
    the answer is 99.0kJ

    Explanation:

    I took the test in chemistry
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