Ask Question
1 October, 09:39

If you reacted 450 g of trimethylgallium with 300 g of arsine, what mass of GaAs could you make?

+1
Answers (1)
  1. 1 October, 10:37
    0
    556.88 g.

    Explanation:

    Firstly, we need to write the balanced chemical reaction:

    (CH₃) ₃Ga + AsH₃ → GaAs + 3 CH₄

    It is now a stichiometric oriented problem; 1.0 mole of trimethyl gallium ((CH₃) ₃Ga) reacts with 1.0 mole of arsine (AsH₃) to produce 1.0 mole of gallium arsenide (GaAs) and 3.0 moles of methane (CH₄). Now, we need to calculate the number of moles (n) of the reacting 450.0 g of trimethyl gallium with 300.0 g of arsine using the relation:

    n = mass / molar mass,

    Molar mass of trimethyl gallium ((CH₃) ₃Ga) = 114.827 g/mol and molar mass of arsine (AsH₃) = 77.95 g/mole. n of trimethyl gallium ((CH₃) ₃Ga) = mass / molar mass = (450.0 g) / (114.827 g/mole) = 3.92 mole. n of arsine (AsH₃) = mass / molar mass = (300.0 g) / (77.95 g/mole) = 3.85 mole. The limiting reactant here is arsine (AsH₃) that it has the lower number of moles. From the stichiometry; 1.0 mole of trimethyl gallium ((CH₃) ₃Ga) reacts with 1.0 mole of arsine (AsH₃) to produce 1.0 mole of gallium arsenide GaAs. Thus, 3.85 mole of arsine (AsH₃) reaacts with 3.92 mole of trimethyl gallium ((CH₃) ₃Ga) (which is slightly excess) to produce 3.85 mole of gallium arsenide (GaAs). Now, we can calculate the mass of the produced gallium arsinate from the relation: mass = n x molar mass. Molar mass of gallium arsenide (GaAs) = 144.645 g/mol. Mass of gallium arsenide (GaAs) = (3.85 mole) (144.645 g/mol) = 556.88 g.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If you reacted 450 g of trimethylgallium with 300 g of arsine, what mass of GaAs could you make? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers