At a constant temperature, 600 mL of an ideal gas is at a pressure of 760 mmHg. If the volume is decreased to 300 mL, the pressure of the gas will be

1520mmHg

Explanation:

Data obtained from the question include:

V1 (initial volume) = 600 mL

P1 (initial pressure) = 760 mmHg

V2 (final volume) = 300 mL

P2 (final pressure) =.?

Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:

P1V1 = P2V2

760 x 600 = P2 x 300

Divide both side by 300

P2 = (760 x 600) / 300

P2 = 1520mmHg

The final pressure of the gas is 1520mmHg