A gas at 1.00 atm occupies 5.00 Liters what would the pressure be with the volume at 10.00 L I'd f the temperature remains constant

0.5 atm

Explanation:

Data obtained from the question include:

P1 (initial pressure) = 1 atm

V1 (initial volume) = 5L

V2 (final volume) = 10L

P2 (final pressure) = ?

The gas is obeying Boyle's law since the temperature is constant.

Using the Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:

P1V1 = P2V2

1 x 5 = P2 x 10

Divide both side by 10

P2 = (1 x 5) / 10

P2 = 0.5 atm

Therefore, the pressure is 0.5 atm