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8 December, 09:51

What is the molarity of the solution produced when 85.6 g of hydrochloric acid (HCl) is dissolved in enough water to prepare 385 mL of solution?

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  1. 8 December, 12:38
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    6.09 M

    Explanation:

    M (HCl) = 1 + 35.5 = 36.5 g/mol

    85.6 g * 1 mol/36.5 g = 2.3452 mol HCl

    Molarity = mol solute / L solution = 2.3452 mol/0.385 L = 6.09 mol/L = 6.09 M
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