Ask Question
Today, 10:41

Calculate the empirical formula the compound with the following percent composition: 27.59%C 1.15%H 16.09%N 55.17%O

+3
Answers (1)
  1. Today, 14:22
    0
    Answer: C2HNO3

    Explanation: C = 27.59/12.011 = 2.297

    H = 1.15/1.008 = 1.1409

    N = 16.09/14.007 = 1.1487

    O = 55.17/15.999 = 3.4483

    Divide by smallest result:

    C = 2

    H=1

    N=1

    O = 3

    Empirical formula = C2HNO3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the empirical formula the compound with the following percent composition: 27.59%C 1.15%H 16.09%N 55.17%O ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers