Given 8.25 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

10.87 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow,

H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH → H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O

According to equation,

88.11 g (1 mol) Butanoic Acid produces = 116.16 g (1 mol) Ethyl Butyrate

So,

8.25 g Butanoic Acid will produce = X g of Ethyl Butyrate

Solving for X,

X = (8.25 g * 116.16 g) : 88.11 g

X = 10.87 g of Ethyl Butyrate