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12 September, 05:54

The half-life of cesium-137 is 30 years. Suppose we have a 200-mg sample. (a) Find the mass that remains after t years.

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  1. 12 September, 06:25
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    Given:

    Half life (t^ 1/2) : 30 years

    A0 (initial mass of the substance) : 200 mg.

    Now we know that

    A = A0 / [2 ^ (t/√t) ]

    Where A is the mass that remains after t years.

    A0 is the initial mass

    t is the time

    t^1/2 is the half life

    Substituting the given values in the above equation we get

    A = [200 / 2^ (t/30) ] mg

    Thus the mass remaining after t years is [200 / 2^ (t/30) ] mg
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