The temperature of a 6.0-g sample of glass changed from 20°C to 45°C when it absorbed 550 J of heat. What is the specific heat of this glass sample?

A. 130 J/g•°C

B. 2300 J/g•°C

C. 0.27 J/g•°C

D. 3.7 J/g•°C

The answer is D

the formula you need to use is Q=mc (delta) t the delta is usually written as a triangle

rearrange this to make c the subject as this is the specific heat capacity

so you get c=Q / (m*tempchange)

delta t means temp change btw

plug in you values so 550 / (6*25)

and you get 3.666666

to 1 decimal place = 3.7

Answer is: D / 3.7 J/g. C