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28 September, 14:35

What is the molarity of 3.0 L of solution containing 4.0 moles MgO

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  1. 28 September, 18:18
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    v=3.0L (to calculate M, volume must be in L)

    n=4.0 moles

    M=n/v (formula molarity)

    =4.0/3.0

    =1.333M
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