For the reaction represented by the equation Pb (NO3) 2 + 2KI → PbI2 + 2KNO3, how many moles of lead iodide are produced from 3.0 moles of potassium iodide when Pb (NO3) 2 is in excess?
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Home » Chemistry » For the reaction represented by the equation Pb (NO3) 2 + 2KI → PbI2 + 2KNO3, how many moles of lead iodide are produced from 3.0 moles of potassium iodide when Pb (NO3) 2 is in excess?