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17 May, 16:37

Determine the Ka for CH3NH3 + at 25*C. The Kb for CH3NH2 is 4.4 x 10-4.

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  1. 17 May, 19:56
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    Ka = 2.3 x 10^-11

    Explanation:

    so Ka x Kb = Kw where Kw=10^-14 at 25 degrees Celsius

    plugging in Kb and Kw, we have

    Ka x 4.4 x 10^-4 = 10^-14

    solving for Ka,

    Ka = (10^-14) / (4.4 x 10^-4)

    Ka = 2.3 x 10^-11
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