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20 December, 08:43

Calculate the molarity of a solution that contains 15.7 g of CaCO3 dissolved in enough water to make 275 mL of solution.

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  1. 20 December, 10:48
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    Molarity = 0.57M

    Explanation:

    m=15.7 Molar mass Of CaCO3 = 100 V=0.275dm3 C=?

    n = m/M = 15.7/100 = 0.157mole

    n = C*V

    0.157 = C * 0.275

    C = 0.57M
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