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3 November, 01:58

1. Calculate the [H] in a solution that has a pH of 9.88.

A) 4.1 M

B) 9.9 M

C) 7.6 x 10'M

D) 1.3 x 10 "M

E) none of these

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Answers (2)
  1. 3 November, 03:32
    0
    The answer to your question is the letter D) [H⁺] = 1.3 x 10⁻¹⁰ M

    Explanation:

    Data

    [H⁺] = ?

    pH = 9.88

    pH measures the [H⁺] in a solution. It has a range from 0 to 14. Acids have a pH from 0 to 6.9, a neutral solution has a pH of 7.0 and alkalis have a pH from 7.1 to 14.

    Formula

    pH = - log [H⁺]

    Substitution

    9.88 = - log[H⁺]

    Simplification

    antilog - 9.88 = [H⁺]

    -Result

    [H⁺] = 1.3 x 10⁻¹⁰ M
  2. 3 November, 04:41
    0
    The answer to the question is D.
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