How many anions are in 0.500 g of MgBr2

Given:

Mass of MgBr2 = 0.500 g

To determine:

Number of anions in 0.500 g MgBr2

Explanation:

Molar mass of MgBr2 = 24 + 2 (80) = 184 g/mol

Moles of MgBr2 = 0.500 g/184 g. mol-1 = 0.00271 moles

Based on stoichiometry-

1 mole of MgBr2 has 1 mole of Mg2 + cations and 2 moles of Br - anions

Therefore, 0.00271 moles of MgBr2 will have: 2 * 0.00271 = 0.00542 moles of Br-

Now,

1 mole of Br - contains 6.023 * 10²³ anions

0.00542 moles of Br - contain: 0.00542 * 6.023*10²³ = 3.264*10²¹ anions

Ans: There are 3.264*10²¹ anions in 0.5 g of MgBr2