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Yesterday, 21:24

Calculate the molarity of hydroxide ion in an aqueous solution that has a poh of 5.00

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  1. Yesterday, 22:56
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    1.00 x 10^-5 M

    Explanation:

    pOH=-log[OH^-]

    so

    [OH^-]=10^ (-pOH)

    =10^-5

    =1.00 x 10^-5 M
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