A 40.8 mol sample of methane gas, CH4 (g), is placed in a

1020 L container at 298 K.

What is the pressure, in atm, of the methane gas?

Express the answer using 3 significant figures.

atm

P = 0.979 atm

Explanation:

Given dа ta:

Number of moles of methane = 40.8 mol

Volume of container = 1020 L

Temperature = 298 K

Pressure of gas = ?

Solution:

According to ideal gas equation,

PV = nRT

P = pressure

V = volume

n = number of moles

R = general gas constant

T = temperature

Now we will put the values,

P = nRT/V

P = 40.8 mol * 0.0821 atm. L/mol. K * 298 K / 1020 L

P = 998.2 atm / 1020

P = 0.979 atm