The molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO2. How many moles of water are used in this reaction?

12.0

72.0

216

528

72.0 molar mass of carbon dioxide (CO2) is 44.01 g/mol. The molar mass of water (H2O) is 18.01 g/mol. A reaction uses 528 g of CO2. How many moles of water are used in this

12.0

Explanation:

Hi, the reaction is:

H2O + CO2 - -> H2CO3

Analyzing the reaction result:

To produce 1 mole of H2CO3 we need 1 mole of H2O for every mole of CO2.

So, the Stoichiometric ratio between H2O and CO2 is 1:1.

Applying the formula:

. n = m/M

Where:

. n = number of moles

. m = mass in grams

M = grams per mol

e

. n = 528 / 44.01 = 11.9972 = 12 mol

es of C02

The Stoichiometric ratio IS 1:1, so the number of moles of water used are the same. (12)