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30 August, 20:03

Carbon dioxide is usually formed when gasoline is burned. If 3.00 L of CO2 is produced at a temperature of 100 °C, what is the temperature of the gas if the volume reduces to 1.00 L?

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  1. 30 August, 20:13
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    Answer: 124.3K

    Explanation:

    Given that,

    Original volume of CO2 (V1) = 3.00 L

    Original temperature of CO2 (T1) = 100°C

    Since unit of temperature is Kelvin, convert 100°C to Kelvin by adding 273 to 100°C

    (100°C + 273K = 373K)

    New volume V2 = 1.00 L

    New temperature T2 = ?

    Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

    V1/T1 = V2/T2

    3.00L/373K = 1.00L/T2

    To get the value of T2, cross multiply

    3.00L x T2 = 1.00L x 373K

    3.00LT2 = 373LK

    Divide both sides by 3.00L

    3.00LT2/3.00L = 373LK/3.00L

    T2 = 124.3K

    Thus, the temperature of the gas becomes 124.3 Kelvin
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