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28 February, 17:09

At what pressure would 14.4 grams of oxygen gas occupy 7.5 liters at a temperature of 375 K?

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  1. 28 February, 18:55
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    1.85 atm.

    Explanation:

    We can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the gas in L (V = 7.5 L).

    n is the no. of moles of the gas in mol (n = mass/moar mass = 14.4 g/32.0 g/mol = 0.45 mol).

    R is the general gas constant (R = 0.0821 L. atm/mol. K).

    T is the temperature of the gas in K (T = 375 K).

    ∴ P = nRT/V = (0.45 mol) (0.0821 L. atm/mol. K) (375 K) / (7.5 L) = 1.85 atm.
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