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3 June, 05:46

N2 (g) + 3H2 (g) - > 2NH 3 (g)

Calculate the mass in g of Ammonia (NH3) if you react 10.0g of hydrogen with excess nitrogen.

a.) 17.04 g

b.) 84.4 g

c.) 56.2 g

d.) 85.2 g

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Answers (1)
  1. 3 June, 06:17
    0
    None of the options are correct. The correct answer is:

    56.67g

    Explanation:

    N2 + 3H2 - > 2NH3

    Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

    Mass of NH3 from the balanced equation = 2 x 17 = 34g

    Molar Mass of H2 = 2x1 = 2g/mol

    Mass of H2 from the balanced equation = 3 x 2 = 6g

    From the equation,

    6g of H2 produced 34g of NH3.

    Therefore, 10g of H2 will produce = (10 x 34) / 6 = 56.67g of NH3

    Therefore, 56.67g of NH3 are produced
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