21.7 mL of gas at 98.8 kPa is allowed to expand at constant

temperature into a 52.7 mL container. What is the new

pressure of the gas?

kPa.

Answer: 40.68 kPa

Explanation:

Given that,

Original volume of gas V1 = 21.7 mL

Original pressure of gas P1 = 98.8 kPa

New volume of gas V2 = 52.7 mL

New pressure of gas P2 = ?

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

98.8 kPa x 21.7 mL = P2 x 52.7L

2143.96 kPa L = 52.7 L x P2

P2 = 2143.96 kPa L / 52.7 L

P2 = 40.68 kPa

Thus, the new pressure of the gas is 40.68 kPa.