Ask Question
14 July, 09:52

How many Br - ions are there in 2.51 grams of AlBr3

+1
Answers (1)
  1. 14 July, 12:40
    0
    Answer is: there are 1.7·10²² Br⁻ ions.

    m (AlBr₃) = 2.51 g; mass of aluminium bromide.

    n (AlBr₃) = m (AlBr₃) : M (AlBr₃).

    n (AlBr₃) = 2.51 g : 266.7 g g/mol.

    n (AlBr₃) = 0.0094 mol; amount of substance.

    In one mol of aluminium bromide there are three moles of bromine anions:

    n (Br⁻) = 3 · 0.0094 mol.

    n (Br⁻) = 0.028 mol.

    N (Br⁻) = n (Br⁻) · Na (Avogadro constant).

    N (Br⁻) = 0.028 mol · 6.022·10²³ 1/mol.

    N (Br⁻) = 1.7·10²².
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many Br - ions are there in 2.51 grams of AlBr3 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers