How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 0.98 atm and a temperature of 373 K?

There are 1, 13 moles of chlorine gas.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV = nRT - --> n = PV/RT

n = 0,98 atm x 35,5 L / 0,082 l atm / K mol x 373 K

n = 1,137448506 mol