a 22.44 g sample of metal absorbs 180.8 J of hear, upon which the temprature of the sample increases from 21.1 °C to 45.0 °C. what is the specific heat of that metal

The specific heat of the metal is 0.0132 J g^-1 °K^-1

Explanation:

The sample of metal absorbs 180.8 J of heat.

Mass of the metal = 22.44 g

Temperature increase = Final temperature - initial temperature

change in temperature = (45 + 273 K) - (21.1 + 273 K) = 318 + 294.1 = 612.1 K

Specific heat of the metal = ?

When raising the temperature of a substance, the heat absorbed is calculated using:

H = m c ΔT

Rearranging and making c the sunject of the formula, we obtain:

c = H / m ΔT

c = 180.8 J / 22.44 g * 612.1 K

c = 180.8 J / 13735.524 g K

c = 0.0132 J g^-1 °K^-1

The specific heat of the metal is 0.0132 J g^-1 °K^-1