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4 April, 06:17

Carbon is allowed to diffuse through a steel plate 13-mm thick. The concentrations of carbon at the two faces are 0.654 and 0.377 kg C/m3 Fe, which are maintained constant. If the preexponential and activation energy are 6.5 * 10-7 m2/s and 82 kJ/mol, respectively, calculate the temperature (in K) at which the diffusion flux is 3.2 * 10-9 kg / (m2-s).

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  1. 4 April, 09:44
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    T = 1177.95 K

    Explanation:

    Equation for diffusion flux is given as;

    J = D (ΔC/Δx) e^ (Qd/RT)

    Where J = 3.2 * 10^ (-9) kg/m². s

    Qd = 82Kj/mol = 82,000 J/mol

    D = 6.5 * 10^ (-7) m²/s

    ΔC = 0.654 - 0.377 = 0.277 kg. C/m³

    Δx = 13mm = 0.013m

    R = 8.314 J/mol. k

    Let's make T the subject of the equation;

    T = Qd / (R In D (ΔC/JΔx))

    T = 82,000 / (8.314 In 6.5 * 10^ (-7) (0.277 / (3.2 * 10^ (-9) x 0.013))

    T = 82000 / (8.314In 4328.125) = 1177.95 K
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