A volume of gas occupies 3.2 L at 2.8 kPa. What would the pressure be if the same volume of gas now occupied 8.1 L?

Answer: 1.09 kPa

Explanation:

Given that,

Original volume V1 = 3.2 L

Original pressure P1 = 2.8 kPa

New pressure P2 = ?

New volume V2 = 8.1 L

Since pressure and volume are given While temperature is constant, apply Boyle's law

P1V1 = P2V2

2.8 kPa x 3.2L = P2 x 8.1L

8.96 kPa L = P2 x 8.2L

P2 = 8.96 kPa L / 8.2L

P2 = 1.09 kPa

Thus, the pressure of the gas would be 1.09 kPa