A volume of gas occupies 1.2 L at 5.1 kPa. What volume would the gas occupy at 2.2 kPa?

Answer: 2.78 L

Explanation:

Given that,

Original volume V1 = 1.2 L

Original pressure P1 = 5.1 kPa

New pressure P2 = 2.2 kPa

New volume V2 = ?

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

5.1 kPa x 1.2L = 2.2 kPa x V2

6.12 kPa L = 2.2 kPa x V2

V2 = 6.12 kPa L / 2.2L

V2 = 2.78 L

Thus, the new volume of the gas would be 2.78 Liters