What is the specific heat of an object that weighs 15 grams and changes temperature from 30°C to 37°C when 50 J of heat is added?

1. 0.48 J/g •°C

2. 0.11 J/g •°C

3. 23.33 J/g •°C

4. 0.09 J/g •°C

0.4762 J/g°C.

Explanation:

It is known that:

The amount of heat released to water = Q = m. c.ΔT.

where, m is the mass of water (m = 15.0 g).

c is the specific heat capacity of water = ? J/g°C.

ΔT is the temperature difference = (final T - initial T = 37.0°C - 30.0°C = 7.0°C).

∴ The specific heat capacity of water = c = Q/m.ΔT = (50.0 J) / (15.0 g) (7.0°C) = 0.4762 J/g°C.