If 15.0 liters of neon at 35.0C is allowed to expand to 50.0 liters, what must the new temperature be to maintain constant pressure?

753.7°C

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 15L

Initial temperature (T1) = 35°C = 35°C + 273 = 308K

Final volume (V2) = 50L

Final temperature (T2) = ... ?

Step 2:

Determination of the new temperature of the Neon gas.

The new temperature of the neon gas can be obtained by using Charles' law since the pressure is constant. This is illustrated below:

V1/T1 = V2/T2

15/308 = 50/T2

Cross multiply to express in linear form

15 x T2 = 308 x 50

Divide both side by 15

T2 = (308 x 50) / 15

T2 = 1026.7K

Step 3:

Conversion of 1026.7K to celsius.

T (°C) = T (K) - 273

T (°C) = 1026.7K

T (°C) = 1026.7 - 273

T (°C) = 753.7°C

Therefore, the new temperature of the Neon gas is 753.7°C