How many moles of dipyrithione contain 6.3*1024 atoms of nitrogen?

Express your answer to two significant figures and include the appropriate units

5.2 moles dipyrithione contain 6.3 * 10^24 atoms of nitrogen

Explanation:

Step 1: Data given

Dipyrithione = C10H8N2O2S2

Number of Avogadro = 6.02 * 10^23

Number of nitrogen atoms = 6.3 * 10^24 atoms

Step 2: Calculate moles nitrogen

Moles nitrogen = atoms nitrogen / number of Avogadro

Moles nitrogen = 6.3 * 10^24 / 6.02 * 10^23

Moles nitrogen = 10.47 moles

Step 3: Calculate moles dipyrithione

In 1 mol dipyrithione we 2 moles N

For 10.47 moles N we have 10.47/2 = 5.2 moles dipyrithione

5.2 moles dipyrithione contain 6.3 * 10^24 atoms of nitrogen